Question

\(0.126 \mathrm{~g}\) of an acid is needed to completely neutralize \(20 \mathrm{ml} 0.1\) (N) NaOH solution. The equivalent weight of the acid is
(A) 53
(B) 40
(C) 45
(D) 63

Answer 1

Ans: (D)
Number of equivalents of acid = number of equivalents of base
$$
\begin{aligned}
&=\frac{N *}{1000} \\
&=\frac{0.1 \times 20}{1000} \\
&=2 \times 10^{-3}
\end{aligned}
$$
\(2 \times 10^{-3}\) equivalents have mass \(=0.126 \mathrm{~g}\)
1 equivalent has mass \(=\frac{0.126}{2 \times 10^{-3}} \mathrm{~g}=63 \mathrm{~g}\)

Answer 2

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Answer 3

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