Ans: (C)
Weight ratio \(\quad \mathrm{w}_{\mathrm{CH}_{4}}: \mathrm{w}_{\mathrm{SO}_{2}}=1: 2\)
Number of moles, \(n=\frac{w}{M}, \frac{n_{1}}{n_{2}}=\frac{w_{1}}{M_{1}} \times \frac{M_{2}}{w_{2}}\)
\(\frac{\mathrm{n}_{\mathrm{SO}_{2}}}{\mathrm{n}_{\mathrm{CH}_{4}}}=\frac{\mathrm{w}_{\mathrm{SO}_{2}}}{\mathrm{M}_{\mathrm{SO}_{2}}} \times \frac{\mathrm{M}_{\mathrm{CH}_{4}}}{\mathrm{w}_{\mathrm{CH}_{4}}}=\frac{2}{64} \times \frac{16}{1}=\frac{1}{2} \therefore\) mole ratio \(\mathrm{SO}_{2}: \mathrm{CH}_{4}=1: 2\)
\(\therefore\) ratio of number of molecules of \(\mathrm{SO}_{2}\) and \(\mathrm{CH}_{4}=1: 2\)
