Question

\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{~F}^{18}\) is a \(\mathrm{F}^{8}\) radio-isotope labelled organic compound. \(\mathrm{P}^{8}\) decays by positron emission. the product resulting or decay is
(A) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{18}\)
(B) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{Ar}^{19}\)
(C) \(\mathrm{B}^{12} \mathrm{C}_{5} \mathrm{H}_{5} \mathrm{~F}\)
(D) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{16}\)

Answer 1

Ans:(A)
$$
\begin{aligned}
&{ }_{9}^{\mathrm{F}^{18}} \rightarrow{ }_{\mathrm{x}} \mathrm{E}^{\mathrm{y}}+{ }_{+1} \mathrm{e}^{0} \\
&\mathrm{x}=8, \mathrm{y}=18, \therefore \mathrm{E}^{\mathrm{y}}={ }_{8} \mathrm{O}^{18} \\
&\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{18}
\end{aligned}
$$

Answer 2

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Answer 3

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