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Dissolving NaCN in de-ionized water will result in a solution having
(A) \(\mathrm{pH}<7\)
(B) \(\mathrm{pH}=7\)
(C) \(\mathrm{pOH}=7\)
(D) \(\mathrm{pH}>7\)

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Ans:(D)
 \(\mathrm{CN}^{-}+\mathrm{H}_{2} \mathrm{O}\) (3) \(\mathrm{OH}^{-}+\mathrm{HCN}\)
Hence solution will be alkaline due to anionic hydrolysis

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