Question

\(\mathrm{PbCl}_{2}\) is insoluble in cold water. Addition of \(\mathrm{HCl}\) increases its solubility due to
(A) Formation of soluble complex anions like [PbC]
(B) Oxidation of \(\mathrm{Pb}(\mathrm{II})\) to \(\mathrm{Pb}\) (IV)
(C) Formation of \(\left[\mathrm{Pb}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\)
(D) Formation of polymeric lead complexes

Answer 1

Ans:(A)
Hint \(: \mathrm{PbCl}_{2}(\mathrm{~s})+\mathrm{Cl} \rightarrow[\mathrm{Pb} \mathrm{Cl}](\mathrm{aq})\)
\(\mathrm{PbCl}_{2}(\mathrm{~s})+2 \mathrm{Cl} \rightarrow\left[\mathrm{Pb} \mathrm{Cl}_{4}\right]^{2}(\mathrm{aq})\)
Addition of chloride ions to a suspension of PbClgives rise to soluble complex ion. In these reactions the additional chlorides break up the chloride bridges that comprise the polymeric framework of solid Pb2O(s)

Answer 2

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Answer 3

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