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You are supplied with \(500 \mathrm{ml}\) each of \(2 \mathrm{~N} \mathrm{HCl}\) and \(5 \mathrm{~N} \mathrm{HCl}\). What is the maximum volume of \(3 \mathrm{M} \mathrm{HCl}\) that you can prepare using only these two solutions?
(A) \(250 \mathrm{ml}\)
(B) \(500 \mathrm{ml}\)
(C) \(750 \mathrm{ml}\)
(D) \(1000 \mathrm{ml}\)

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Ans : (C)
\(\because\) We have to prepare maximum volume solution of \(3 \mathrm{~N}\). (3 \(\mathrm{N}\) is same as \(3 \mathrm{M}\) for \(\mathrm{HCl}\) ) Hence we will take al \(500 \mathrm{ml}\) of \(2 \mathrm{~N}\) solution and \(\mathrm{x} \mathrm{ml}\) of \(5 \mathrm{~N}\) solution.
\(\begin{array}{ll}\therefore \quad & 500 \times 2+x \times 5=3(x+500) \\ & 1000+5 x=3 x+1500 \\ & 2 x=500 \\ & x=250 \mathrm{ml}\end{array}\)
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