0 votes
in Sets, relations and functions by
\(\int 2^{x}\left(f^{\prime}(x)+f(x) \log 2\right) d x\) is equal to
(A) \(2^{x} f^{\prime}(x)+c\)
(B) \(2^{x} \log 2+c\)
(C) \(2^{x} f(x)+c\)
(D) \(2^{x}+c\)

3 Answers

0 votes
by (12.2k points)
Ans: (C)
 \(\int 2^{x}\left(f^{\prime}(x)+f(x) \log 2\right) d x=I\)
$$
\begin{aligned}
&\text { Let } g(x)=2^{x} f(x) \\
&\begin{aligned}
\Rightarrow g^{\prime}(x) &=2^{x} f^{\prime}(x)+2^{x} f(x) \log 2 \\
&=2^{x}\left(f^{\prime}(x)+f(x) \log 2\right)
\end{aligned} \\
&\therefore I=\int g^{\prime}(x) d x=g(x)+c=2^{x} f(x)+c
\end{aligned}
$$
0 votes
by
buy cialis 5mg online <a href="https://ordergnonline.com/">cialis 5mg canada</a> buy generic ed pills over the counter
0 votes
by
tadalafil india <a href="https://ordergnonline.com/">buy tadalafil 40mg for sale</a> where to buy otc ed pills
...