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The value of \(\underset{n \rightarrow \infty}{\text { It }}\left\{\frac{\sqrt{n+1}+\sqrt{n+2}+\ldots .+\sqrt{2 n-1}}{n^{3 / 2}}\right\}\) is
(A) \(\frac{2}{3}(2 \sqrt{2}-1)\)
(B) \(\frac{2}{3}(\sqrt{2}-1)\)
(C) \(\frac{2}{3}(\sqrt{2}+1)\)
(D) \(\frac{2}{3}(2 \sqrt{2}+1)\)

3 Answers

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Ans: (A)
$$
\begin{aligned}
\text { Hint } &: \operatorname{lt}_{n \rightarrow \infty}\left(\frac{\sqrt{n+1}+\sqrt{n+2}+\sqrt{n+3}+\ldots \ldots+\sqrt{2 n-1}}{n^{3 / 2}}\right) \\
=& \operatorname{It}_{n \rightarrow \infty}\left(\sqrt{1+\frac{1}{n}}+\sqrt{1+\frac{2}{n}}+\ldots \ldots \ldots+\sqrt{1+\frac{n-1}{n}}\right) \frac{1}{n} \\
=& \operatorname{It}_{n \rightarrow \infty} \sum_{r=1}^{n-1} \frac{1}{n} \sqrt{1+\frac{r}{n}} \\
=& \int_{0}^{1} \sqrt{1+x} d x=\frac{2}{3} \cdot(2 \sqrt{2}-1)
\end{aligned}
$$
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