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A quadratic polynomial, whose zeroes are \(-3\) and 4 , is
(A) \(x^{2}-x+12\)
(B) \(x^{2}+x+12\)
(C) \(\left(x^{2} / 2\right)-(x / 2)-6\)
(D) \(2 x^{2}+2 x-24\)

3 Answers

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(C) \(\left(x^{2} / 2\right)-(x / 2)-6\)
Explanation:
Sum of zeroes, \(\alpha+\beta=-3+4=1\)
Product of Zeroes, \(\alpha \beta=-3 \times 4-12\)
Therefore, the quadratic polynomial becomes,
\(x^{2}-(\) sum of zeroes \() x+\) (product of zeroes)
\(=x^{2}-(\alpha+\beta) x+(\alpha \beta)\)
\(=x^{2}-(1) x+(-12)\)
\(=x^{2}-x-12\)
Hence, option (C) is the correct answer.
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