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if \(\log _{0.3}(x-1)<\log _{009}(x-1)\), then \(x\) lies in the interval
0
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asked
Dec 8, 2021
in
Sets, relations and functions
by
anonymous
edited
Dec 20, 2021
by
deepak01
if \(\log _{0.3}(x-1)<\log _{009}(x-1)\), then \(x\) lies in the interval
(A) \((2, \infty)\)
(B) \((1,2)\)
(C) \((-2,-1)\)
(D) None of these
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1
Answer
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answered
Dec 20, 2021
by
deepak01
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Ans : (A)
\(: \log _{03}(x-1)<\log _{(0.3)}^{2}(x-1) \Rightarrow \log _{03}(x-1)^{2}<\log _{(03)}(x-1) \Rightarrow(x-1)^{2}>x-1 \quad(0.3<1)\)
\(\Rightarrow(x-1)(x-2)>0 \Rightarrow x<1, x>2 \Rightarrow x>2 \quad(x \neq 1)\)
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