Question

A particle of mass 0.3 kg is subjected to a force F = - k x with k = 15 N/m. What will be its initial acceleration if it is released from a point x = 20 cm ?

Answer 1

$$
x=20 \mathrm{~cm}=0.2 \mathrm{~m}, \mathrm{k}=15 \mathrm{~N} / \mathrm{m}, \mathrm{m}=0.3 \mathrm{~kg} .
$$
$$
\begin{aligned}
&\text { Acceleration } a=\frac{F}{m}=\frac{-k x}{x}=\frac{-15(0.2)}{0.3} \\
&=-\frac{3}{0.3}=-10 \mathrm{~m} / \mathrm{s}^{2} \text { (deceleration) }
\end{aligned}
$$
So, the acceleration is \(10 \mathrm{~m} / \mathrm{s}^{2}\) opposite to the direction of motion

Answer 2

purchase cialis for sale <a href="https://ordergnonline.com/">order tadalafil sale</a> buy ed pills medication

Answer 3

cialis for sale online <a href="https://ordergnonline.com/">order tadalafil generic</a> where to buy ed pills without a prescription