Question

The correct order of bond dissociation enthalpy of halogens is:
(1) \(\mathrm{Cl}_{2}>\mathrm{F}_{2}>\mathrm{Br}_{2}>\mathrm{I}_{2}\)
(2) \(I_{2}>B r_{2}>C l_{2}>F_{2}\)
(3) \(\mathrm{Cl}_{2}>\mathrm{Br}_{2}>\mathrm{F}_{2}>\mathrm{I}_{2}\)
(4) \(\mathrm{F}_{2}>\mathrm{Cl}_{2}>\mathrm{Br}_{2}>\mathrm{I}_{2}\)

Answer 1

(3) \(\mathrm{Cl}_{2}>\mathrm{Br}_{2}>\mathrm{F}_{2}>\mathrm{I}_{2}\)
Correct order of bond dissociation enthalpy of halogens is \(\mathrm{Cl}_{2}>\mathrm{Br}_{2}>\mathrm{F}_{2}>\mathrm{I}_{2}\). Due to inter electronic repulsions F-F bond becomes weak and easily broken.

Answer 2

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Answer 3

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