Question

If \(A=\left\{5^{n}-4 n-1: n \in N\right\}\) and \(B=\{16(n-1): n \in N\}\), then
(A) \(A=B\)
(B) \(A \cap B=\phi\)
(C) \(A \subseteq B\)
(D) \(B \subseteq A\)

Answer 1

Ans: (C)
\(5^{n}-4 n-1=(4+1)^{n}-4 n-1=16 k, k \in Z, A\) is a set of some multiple of 16 while set \(B\) is the set of all consecutive multiple of \(16 .\)

Answer 2

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Answer 3

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