0 votes
in Kinematics by (90.1k points)
The following four wires are made of the same material. Which of these will have the largest extension when the same tension is applied?

(a) ) length = 200 cm, diameter =2 mm

(b) length = 300 cm, diameter -=3 mm

(c) length = 50 cm, diameter = 0.5 mm

(d) length = 100 cm, diameter = 1

3 Answers

0 votes
by (90.1k points)
Explanation:
Young's modulus,
where \(F\) is the force applied, \(L\) is the length, \(D\) is the diameter and \(\Delta L\) is the extension of the wire respectively. As each wire is made up of same material therefore their Young's modulus is same fol each wire. For all the four wires. Y, \(F\) (= tension) are the same.
\(\therefore \quad \Delta L \propto \frac{L}{D^{2}}\)
In (a) \(\frac{L}{D^{2}}=\frac{200 \mathrm{~cm}}{(0.2 \mathrm{~cm})^{2}}=5 \times 10^{3} \mathrm{~cm}^{-1}\)
In (b) \(\frac{L}{D^{2}}=\frac{300 \mathrm{~cm}}{(0.3 \mathrm{~cm})^{2}}=3.3 \times 10^{3} \mathrm{~cm}^{-1}\)
In (c) \(\frac{L}{D^{2}}=\frac{50 \mathrm{~cm}}{(0.05 \mathrm{~cm})^{2}}=20 \times 10^{3} \mathrm{~cm}^{-1}\)
In (d) \(\frac{L}{D^{2}}=\frac{100 \mathrm{~cm}}{(0.1 \mathrm{~cm})^{2}}=10 \times 10^{3} \mathrm{~cm}^{-1}\)
Hence, \(\Delta \mathrm{L}\) is maximum in (c).
0 votes
by
cialis black <a href="https://ordergnonline.com/">order tadalafil 40mg without prescription</a> best erection pills
0 votes
by
order generic tadalafil 40mg <a href="https://ordergnonline.com/">buy tadalafil pill</a> where can i buy ed pills

Related questions

...