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If the function \(f: \mathbb{R} \rightarrow R\) is defined by \(f(x)=\left(x^{2}+1\right)^{35} \forall \in \mathbb{R}\), then \(f\) is
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Dec 8, 2021
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Dec 20, 2021
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If the function \(f: \mathbb{R} \rightarrow R\) is defined by \(f(x)=\left(x^{2}+1\right)^{35} \forall \in \mathbb{R}\), then \(f\) is
(A) one-one but not onto
(B) onto but not one-one
(C) neither one-one nor onto
(D) both one-one and onto
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Ans(C)
\(f(x)=\left(x^{2}+1\right)^{35}\)
Since \(f(x)\) is even function hence not one one and \(f(x)>0 \forall x \in R\) hence not onto
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