Question

Equal masses of \(\mathrm{H}_{2}, \mathrm{O}_{2}\) and methane have been taken in a container of volume \(\mathrm{V}\) at temperature \(27^{\circ} \mathrm{C}\) in identical conditions. The ratio of the volumes of gases \(\mathrm{H}_{2}: \mathrm{O}_{2}\) : methane would be
(a) \(8: 16: 1\)
(b) \(16: 8: 1\)
(c) \(16: 1: 2\)
(d) \(8: 1: 2\)

Answer 1

The correct option is : (c) 16:1:2
Explanation:
According to Avogadro's hypothesis, ratio of the volumes of gases will be equal to the ratio of their no. of moles.
So, no. of moles \(=\frac{\text { Mass }}{\text { Mol. mass }}\)
\(n_{\mathrm{H}_{2}}=\frac{w}{2} ; n_{\mathrm{O}_{2}}=\frac{w}{32} ; n_{\mathrm{CH}_{4}}=\frac{w}{16}\)
So, the ratio is \(\frac{w}{2}: \frac{w}{32}: \frac{w}{16}\) or \(16: 1: 2\).