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If \(\alpha\) and \(\beta\) are roots of \(a x^{2}+b x+c=0\) then the equation whose roots are \(\alpha^{2}\) and \(\beta^{2}\) is
(A) \(a^{2} x^{2}-\left(b^{2}-2 a c\right) x+c^{2}=0\)
(B) \(a^{2} x^{2}+\left(b^{2}-a c\right) x+c^{2}=0\)
(C) \(a^{2} x^{2}+\left(b^{2}+a c\right) x+c^{2}=0\)
(D) \(a^{2} x^{2}+\left(b^{2}+2 a c\right) x+c^{2}=0\)

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Ans: (A)
 Let \(y=x^{2} \Rightarrow x=\sqrt{y}\)
putting \(\sqrt{y}\) in the given equation
$$
a y+b \sqrt{y}+c=0 \Rightarrow b \sqrt{y}=-a y-c \quad \Rightarrow b^{2} y=a^{2} y^{2}+c^{2}+2 a c y
$$
$$
\Rightarrow \mathrm{a}^{2} \mathrm{y}^{2}-\left(\mathrm{b}^{2}-2 \mathrm{ac}\right) \mathrm{y}+\mathrm{c}^{2}=0
$$
So the required quadratic equation is \(a^{2} x^{2}-\left(b^{2}-2 a c\right) x+c^{2}=0\)
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