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If the equation x2cx+d=0 has roots equal to the fourth powers of the roots of x2+ax+b=0, where a2>4b, then the roots of x24bx+2b2c=0 will be
(A) both real
(B) both negative
(C) both positive
(D) one positive and one negative

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Ans: (A, D)
Hint : x24bx+2b2c=0
let α1,β1 be roots
α1,β1=2b2c=2b2(a44a2b+2b2)=a2(4ba2)<0
Hence one positive and one negative
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