45× \(6.023 \times 10^{23}\) atoms/mole atoms are contained in one mole of sucrose \(\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right)\).
Explanation :-
1 mole of sucrose contains
\(6.023 \times 10^{23}\) molecules
\(\because 1\) molecule of sucrose has 45 atoms
\(\therefore 6.023 \times 10^{23}\) molecule of sucrose has
\(45 \times 6.023 \times 10^{23}\) atoms \(/\) mole