Question

Find quadratic polynomial whose zeroes are 3 and - 3.

Answer 1

Let the zeroes of the quadratic polynomial be
$$
\alpha=3, \beta=-3
$$
Then, \(\alpha+\beta=3+(-3)=0\)
$$
a \beta=3 \times(-3)=-9
$$
Sum of zeroes \(=\alpha+\beta=0\)
Product of zeroes \(=\alpha \beta=-9\)
Then, the quadratic polynomial
$$
\begin{aligned}
&=x^{2}-(\text { sum of zeroes }) x+\text { product of zeroes } \\
&=x^{2}-(0) x+(-9) \\
&=x^{2}-9
\end{aligned}
$$

Answer 2

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Answer 3

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