Question

The co-ordinate of a point on the auxiliary circle of the ellipse \(x^{2}+2 y^{2}=4\) corresponding to the point on the ellipse whose eccentric angle is \(60^{\circ}\) will be
(A) \((\sqrt{3}, 1)\)
(B) \((1, \sqrt{3})\)
(C) \((1,1)\)
(D) \((1,2)\)

Answer 1

Ans: (B)
Hint: \(\frac{x^{2}}{4}+\frac{y^{2}}{2}=1\)
Equation of auxiliary circle is \(x^{2}+y^{2}=4\)
\(\therefore\) Point on the auxiliary circle is \(p\left(2 \cos 60^{\circ}, 2 \sin 60^{\circ}\right)\) \(p(1, \sqrt{3})\)

Answer 2

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Answer 3

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