0 votes
in CBSE by (90.1k points)
For the reaction R P, the concentration of a reactant changes from 0.03 to 0.22 M in 25 minutes. Calculate the average rate of reaction using units of time both in minutes and seconds.

4 Answers

0 votes
by (90.1k points)
Average rate =
\(-\left[\frac{\text { Final concentration }-\text { Initial concentration }}{\text { Time interval }}\right]\) \(=-\frac{\Delta[\mathrm{R}]}{\Delta \mathrm{t}}\) \(=-\left[\frac{\left[\mathrm{R}_{2}\right]-\left[\mathrm{R}_{1}\right]}{\mathrm{t}_{2}-\mathrm{t}_{1}}\right]=-\left[\frac{0.02-0.03}{25}\right]\) \(=-\left[\frac{-0.01}{25}\right]\) Average rate \(=4 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~min}^{-1}\) \(4 \times 10^{-4}\) \(60 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\) \(=6.66 \times 10^{-6} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\) Hence average rate \(=4 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~min}^{-1}\) Average rate \(=6.66 \times 10^{-6} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\)
\(4 \times 10^{-4}\)
60 mol \(L^{-1} S^{-1}\)
\(=6.66 \times 10^{-6} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\)
Hence average rate \(=4 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~min}^{-1}\)
Average rate \(=6.66 \times 10^{-6} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\)
0 votes
by
cialis overnight shipping <a href="https://ordergnonline.com/">cialis in usa</a> generic ed drugs
0 votes
by
tadalafil medication <a href="https://ordergnonline.com/">order tadalafil 40mg without prescription</a> buy ed meds
0 votes
by
buy prednisone canadian pharmacy: https://prednisone1st.store/# how to get prednisone tablets

Related questions

Welcome to Admisure, where you can ask questions and receive answers from other members of the community.
...