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The equation of the straight line passing through the point \((4,3)\) and making intercepts on the co-ordinate axes whose sum is \(-1\) is
(A) \(\frac{x}{2}-\frac{y}{3}=1\)
(B) \(\frac{x}{-2}+\frac{y}{1}=1\)
(C) \(-\frac{x}{3}+\frac{y}{2}=1\)
(D) \(\frac{x}{1}-\frac{y}{2}=1\)

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Ans : \((A, B)\)

Hint : Let line be \(\frac{x}{a}+\frac{y}{b}=1\), then \(a+b=-1\)
$$
\frac{4}{a}-\frac{3}{1+a}=1 \Rightarrow a=\pm 2
$$
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