Question

If the distance between two consecutive base pairs is $0.34 \mathrm{~nm}$ and the total number of base pairs of a DNA double helix in a typical mammalian cell is $6.6 \times 10^{9}$ bp, then the length of the DNA is approximately:
A $2.0$ meters
B $2.5$ meters
(c) $2.2$ meters
D $2.7$ meters

Answer 1

Solution:
Length of $\mathrm{DNA}=$ Number of base pairs $\times 0.34 \mathrm{~nm}$
$=6.6 \times 10^{9} \times 0.34 \mathrm{~nm}$
$=6.6 \times 10^{9} \times 0.34 \times 10^{-9} \mathrm{~m}$
$=2.2 \mathrm{~m}$

Answer 2

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