Question

A spherical conductor of radius \(10 \mathrm{~cm}\) has a charge of \(3.2 \times 10^{-7} \mathrm{C}\) distributed uniformly. What is the magnitude of electric field at a point \(15 \mathrm{~cm}\) from the centre of the sphere ? \(\left(\frac{1}{4 \pi \epsilon_{o}}=9 \times 10^{9} \mathrm{Nm}^{2} / C^{2}\right)\)
A \(1.28 \times 10^{4} \mathrm{~N} / \mathrm{C}\)
(B) \(1.28 \times 10^{5} \mathrm{~N} / \mathrm{C}\)
c \(1.28 \times 10^{6} \mathrm{~N} / \mathrm{C}\)
D \(1.28 \times 10^{7} \mathrm{~N} / \mathrm{C}\)

Answer 1

Solution:
Electric field outside a conducting sphere
$$
\begin{aligned}
&E=\frac{1}{4 \pi \varepsilon \varepsilon} \frac{Q}{r^{2}} \\
&=\frac{9 \times 10^{\circ} \times 3.2 \times 10^{-7}}{225 \times 10^{-4}} \\
&=0.128 \times 10^{6} \\
&=1.28 \times 10^{5} \mathrm{~N} / \mathrm{C}
\end{aligned}
$$

Answer 2

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