Question

A \(40 \mu F\) capacitor is connected to a \(200 \mathrm{~V}, 50 \mathrm{~Hz}\) ac supply. The rms value of the current in the circuit is, nearly :
A \(1.7 \mathrm{~A}\)
B \(2.05 \mathrm{~A}\)
C. \(2.5 \mathrm{~A}\)
D \(25.1 \mathrm{~A}\)

Answer 1

Solution:
The rms value of the current
$$
\begin{aligned}
&i_{\mathrm{rms}}=C \omega \varepsilon_{\mathrm{rms}} \\
&C=40 \times 10^{-6} \mathrm{~F} \\
&\omega=2 \pi f=100 \pi \\
&\varepsilon_{\mathrm{rms}}=200 \mathrm{~V} \\
&\therefore i_{\mathrm{rms}}=200 \times 40 \times 10^{-6} \times 2 \pi \times 50 \\
&=2.5 \mathrm{~A}
\end{aligned}
$$

Answer 2

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Answer 3

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