0 votes
in Kinematics by (90.1k points)
The energy required to break one bond in DNA is \(10^{-20} J\). This value in eV is nearly
A 6
B \(0.6\)
(C) \(0.06\)
D \(0.006\)

1 Answer

0 votes
by (90.1k points)
Solution:
$$
\begin{aligned}
&1 \mathrm{eV}=1.6 \times 10^{-19} \\
&, J \\
&1 J=\frac{1}{1.6 \times 10^{-19}} \mathrm{eV} \\
&10^{-20} J=\frac{10^{-20}}{1.6 \times 10^{-19}} \mathrm{eV} \\
&=0.06 \mathrm{eV}
\end{aligned}
$$

Related questions

...