Question

An iron rod of susceptibility 599 is subjected to a magnetising field of \(1200 \mathrm{~A} m^{-1}\). The permeability of the material of the rod is :
\(\left(\mu_{o}=4 \pi \times 10^{-7} T m A^{-1}\right)\)
(A) \(2.4 \pi \times 10^{-4} \mathrm{TmA}^{-1}\)
В \(8.0 \pi \times 10^{-5} \mathrm{Tm} \mathrm{A}^{-1}\)
c \(2.4 \pi \times 10^{-5} \mathrm{Tm} \mathrm{A}^{-1}\)
D \(2.4 \pi \times 10^{-7} \mathrm{Tm} \mathrm{A}^{-1}\)

Answer 1

Solution:
$$
\begin{aligned}
&\text { Given, } \chi_{m}=599 \\
&\text { Also, } \mu_{r}=1+\chi_{m}=600 \\
&\text { We know, } \mu=\mu_{r} \mu_{o} \\
&\mu=600 \times 4 \pi \times 10^{-7} \\
&\mu=2400 \pi \times 10^{-7} \\
&\mu=2.4 \pi \times 10^{-4} \mathrm{Tm} A^{-1}
\end{aligned}
$$

Answer 2

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Answer 3

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