Question

A charged particle having drift velocity of \(7.5 \times 10^{-4} \mathrm{~m} \mathrm{~s}^{-1}\) in an electric field of \(3 \times 10^{-10} \mathrm{Vm}^{-1}\), has a mobility in \(m^{2} V^{-1} \mathrm{~s}^{-1}\) of:
A \(2.25 \times 10^{15}\)
(B) \(2.5 \times 10^{6}\)
c \(2.5 \times 10^{-6}\)
D \(2.25 \times 10^{-15}\)

Answer 1

Solution:
$$
\begin{aligned}
&\text { Mobility, } \mu=\frac{v_{d}}{E} \\
&=\frac{7.5 \times 10^{-}}{3 \times 10^{-10}} \\
&=2.5 \times 10^{6}
\end{aligned}
$$

Answer 2

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