Question

The number of Faradays(F) required to produce \(20 \mathrm{~g}\) of calcium from molten \(\mathrm{CaCl}_{2}\) (Atomic mass of \(\mathrm{CaCl}_{2} \mathrm{~g} \mathrm{~mol}^{-1}\) ) is :
A 1
B 2
c 3
D 4

Answer 1

Solution:
\(\mathrm{Ca}^{+2}+2 e^{-} \rightarrow \mathrm{Ca}\)
\(2 F\) of electricity deposits 1 mole of \(\mathrm{Ca}(40 \mathrm{~g})\)
To deposite \(20 \mathrm{~g}\) of \(\mathrm{Ca}\), the number of Faraday required \(=1\)

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