The number of Faradays(F) required to produce $20 \mathrm{~g}$ of calcium from molten $\mathrm{CaCl}_{2}$ (Atomic mass of $\mathrm{CaCl}_{2} \mathrm{~g} \mathrm{~mol}^{-1}$ ) is :

Question

Page:

kritika · Answer 1 · 2021-12-30T09:14:58+0000

Solution:

$\mathrm{Ca}^{+2}+2 e^{-} \rightarrow \mathrm{Ca}$

$2 F$ of electricity deposits 1 mole of

$\mathrm{Ca}(40 \mathrm{~g})$
To deposite

$20 \mathrm{~g}$ of

$\mathrm{Ca}$ , the number of Faraday required

$=1$

Your answer