Question

The direction ratios of the normal to the plane passing through the points \((1,2,-3),(-1,-2,1)\) and parallel to \(\frac{x-2}{2}=\frac{y+1}{3}=\frac{z}{4}\) is
(A) \((2,3,4)\)
(B) \((14,-8,-1)\)
(C) \((-2,0,-3)\)
(D) \((1,-2,-3)\)

Answer 1

Ans: (B)
Hint : Let the direction ratios of the normal to the plane be \((a, b, c)\), then
$$
\left.\begin{array}{c}
2 a+3 b+4 c=0 \\
\text { and }-2 a-4 b+4 c=0
\end{array}\right\} \Rightarrow \frac{a}{28}=\frac{b}{-16}=\frac{c}{-2} \therefore(a, b, c) \equiv(14,-8,-1)
$$

Answer 2

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Answer 3

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