Question

The equation of the plane, which bisects the line joining the points \((1,2,3)\) and \((3,4,5)\) at right angles is,
(A) \(x+y+z=0\)
(B) \(x+y-z=9\)
(C) \(x+y+z=9\)
(D) \(x+y-z+9=0\)

Answer 1

Ans: (C)
Hint : Midpoint of the line segment joining \((1,2,3)\) and \((3,4,5)\) is \((2,3,4)\) and the d.r.'s joining them are \((2,2,2) \equiv(1,1,1)\) \(\therefore\) the required equation of the plane is \((x-2)+(y-3)+(z-4)=0 \Rightarrow x+y+z=9\)

Answer 2

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Answer 3

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