Question

The equation of the plane, which bisects the line joining the points $(1,2,3)$ and $(3,4,5)$ at right angles is,
(A) $x+y+z=0$
(B) $x+y-z=9$
(C) $x+y+z=9$
(D) $x+y-z+9=0$

Answer 1

Ans: (C)
Hint : Midpoint of the line segment joining $(1,2,3)$ and $(3,4,5)$ is $(2,3,4)$ and the d.r.'s joining them are $(2,2,2) \equiv(1,1,1)$ $\therefore$ the required equation of the plane is $(x-2)+(y-3)+(z-4)=0 \Rightarrow x+y+z=9$

Answer 2

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Answer 3

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