Question

Q. The outermost electronic configuration of the most electronegative element is
A \(n s^{2} n p^{3}\)
B \(n s^{2} n p^{4}\)
\(10^{\circ}\)
C. \(n s^{2} n p^{5}\)
D \(n s^{2} n p^{6}\)

Answer 1

Solution:
Fluorine, a halogen, is the most electronegative atom, has the electronic configuration \(2 s^{2} 2 p^{5}\) (valence shell).