Question

If the given four electronic configurations
(i) \(n=4, l=1\)
(ii) \(\mathrm{n}=4, l=0\)
(iii) \(\mathrm{n}=3, l=2\)
(iv) \(\mathrm{n}=3, l=1\)
are arranged in order of increasing energy, then the order will be
(A) (iv) \(<\) (ii) \(<\) (iii) \(<\) (i)
(B) (ii) \(<\) (iv) \(<\) (i) \(<\) (iii)
(C) (i) \(<\) (iii) \(<\) (ii) \(<\) (iv)
(D) (iii) \(<(\mathrm{i})<(\mathrm{iv})<(\mathrm{ii})\)

Answer 1

Ans: (A)
Hint: (i) \(n=4, l=1 \quad 4 \mathrm{p}\) orbital
(ii) \(n=4, l=0 \quad 4\) s orbital
(iii) \(n=3, l=2 \quad 3 d\) orbital
(iv) \(n=3, l=1 \quad\) 3p orbital

Answer 2

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Answer 3

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