Question

Q. The correct Biot-Savart law in vector form is
A \(d \vec{B}=\frac{\mu_{0}}{4 \pi} \frac{I(d \vec{l} \times \vec{r})}{r^{2}}\)
B \(d \vec{B}=\frac{\mu_{0}}{4 \pi} \frac{I(d \vec{l} \times \vec{r})}{r^{3}}\)
C \(d \vec{B}=\frac{\mu_{0}}{4 \pi} \frac{I d \vec{l}}{r^{2}}\)
D \(d \vec{B}=\frac{\mu_{0}}{4 \pi} \frac{I d \vec{l}}{r^{3}}\)

Answer 1

Solution:
Biot-Savart law in vector form is
$$
\overrightarrow{d B}=\frac{\mu_{0}}{4 \pi} \frac{\overrightarrow{d l} \times \vec{r}}{r^{3}}
$$

Answer 2

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