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Equation of a tangent to the hyperbola 5x2y2=5 and which passes through an external point (2,8) is
(A) 3xy+2=0
(B) 3x+y14=0
(C) 23x3y22=0
(D) 3x23y+178=0

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Ans: (A,C)
Hint : Let the tangent be y=mx±m25
Since it passes through (2,8)(82m)2=m25
3m232m+69=03m29m23m+69=0(3m23)(m3)=0m=3 or 233
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