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Equation of a tangent to the hyperbola
5
x
2
−
y
2
=
5
and which passes through an external point
(
2
,
8
)
is
0
votes
asked
Dec 11, 2021
in
Sets, relations and functions
by
kritika
(
90.1k
points)
edited
Dec 27, 2021
by
kritika
Equation of a tangent to the hyperbola
5
x
2
−
y
2
=
5
and which passes through an external point
(
2
,
8
)
is
(A)
3
x
−
y
+
2
=
0
(B)
3
x
+
y
−
14
=
0
(C)
23
x
−
3
y
−
22
=
0
(D)
3
x
−
23
y
+
178
=
0
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1
Answer
0
votes
answered
Dec 27, 2021
by
kritika
(
90.1k
points)
Ans:
(
A
,
C
)
Hint : Let the tangent be
y
=
m
x
±
√
m
2
−
5
Since it passes through
(
2
,
8
)
⇒
(
8
−
2
m
)
2
=
m
2
−
5
⇒
3
m
2
−
32
m
+
69
=
0
⇒
3
m
2
−
9
m
−
23
m
+
69
=
0
⇒
(
3
m
−
23
)
(
m
−
3
)
=
0
⇒
m
=
3
or
23
3
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