Question

Consider an engine that absorbs 130 cal of heat from a hot reservoir and delivers 30 cal heat to a cold reservoir in each cycle. The engine also consumes \(2 \mathrm{~J}\) energy in each cycle to overcome friction. If the engine works at 90 cycles per minute, what will be the maximum power delivered to the load? [Assume the thermal equivalent of heat is \(4.2 \mathrm{~J} / \mathrm{cal}\) ]
(A) \(816 \mathrm{~W}\)
(B) \(819 \mathrm{~W}\)
(C) \(627 \mathrm{~W}\)
(D) \(630 \mathrm{~W}\)

Answer 1

Ans: (C)
Hint: work done per cycle \(=100 \times 4.2-2=418 \mathrm{~J}\)
Total work done \(=418 \times 90\)
Power \(=\frac{418 \times 90}{60}=627 \mathrm{~W}\)

Answer 2

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Answer 3

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