Question

A thin convex lens is placed just above an empty vessel of depth $80 \mathrm{~cm}$. The image of a coin kept at the bottom of the vessel is thus formed $20 \mathrm{~cm}$ above the lens. If now water is poured in the vessel up to a height of $64 \mathrm{~cm}$, what will be the approximate new position of the image. Assume that refractive index of water is $4 / 3 .$
(A) $21.33 \mathrm{~cm}$ above the lens
(B) $6.67 \mathrm{~cm}$ below the lens
(C) $33.67 \mathrm{~cm}$ above the lens
(D) $24 \mathrm{~cm}$ above the lens
Ans:(A)

Answer 1

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Answer 2

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