Question

The heat of neutralization of a strong base and a strong acid is \(13: 7 \mathrm{kcal}\). The heat released when \(0.6 \mathrm{~mole} \mathrm{HCl}\) solution is added to \(0.25\) mole of \(\mathrm{NaOH}\) is
(A) \(3.425 \mathrm{kcal}\)
(B) \(8.22 \mathrm{kcal}\)
(C) \(11.645 \mathrm{kcal}\)
(D) \(13.7 \mathrm{kcal}\)

Answer 1

Ans(A)

\begin{aligned}
&\text { Ans : (A) } \\
&\text { Hint: } \\
&\qquad \mathrm{t}=0 \quad 0.6 \mathrm{~mol}
\end{aligned} \quad \begin{array}{ccc}
\mathrm{H}^{+} & \mathrm{OH}^{-} & \longrightarrow \mathrm{H}_{2} \mathrm{O} & \text { Heat released }=0.25 \times 13.7=3.421 \mathrm{kcal}
\end{array}

Answer 2

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