Ans: (A)
Hint: Let \(P(\lambda+1,4 \lambda-2,5 \lambda+3)\)
It lies on \(2 x+3 y-4 z+22=0\)
\(\therefore 2(\lambda+1)+3(4 \lambda-2)-4(5 \lambda+3)+22=0\)
\(\therefore 6 \lambda=6 \quad \Rightarrow \lambda=1\)
\(\therefore P=(2,2,8) \quad \therefore P Q=\sqrt{1^{2}+4^{2}+5^{2}}=\sqrt{42}\)