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A positive charge \(Q\) is situated at the centre of a cube. The electric flux through any face of the cube is (in SI units)
(A) \(\frac{Q}{6 \varepsilon_{0}}\)
(B) \(4 \pi \mathrm{Q}\)
(C) \(\frac{Q}{4 \pi \varepsilon_{0}}\)
(D) \(\frac{Q}{6 \pi \varepsilon_{0}}\)

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Ans(A)

Total flux=$$
\frac{Q}{\varepsilon_{0}} \text { using Gauss' law }
$$
\(\therefore\) flux through one face \(=\frac{Q}{6 \varepsilon_{0}}\)
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