Question

If the given four electronic configurations
(i) $n=4, l=1$
(ii) $\mathrm{n}=4, l=0$
(iii) $\mathrm{n}=3, l=2$
(iv) $\mathrm{n}=3, l=1$
are arranged in order of increasing energy, then the order will be
(A) (iv) $<$ (ii) $<$ (iii) $<$ (i)
(B) (ii) $<$ (iv) $<$ (i) $<$ (iii)
(C) (i) $<$ (iii) $<$ (ii) $<$ (iv)
(D) (iii) $<(\mathrm{i})<(\mathrm{iv})<(\mathrm{ii})$

Answer 1

Ans: (A)
Hint: (i) $n=4, l=1 \quad 4 \mathrm{p}$ orbital
(ii) $n=4, l=0 \quad 4$ s orbital
(iii) $n=3, l=2 \quad 3 d$ orbital
(iv) $n=3, l=1 \quad$ 3p orbital

Answer 2

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Answer 3

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