Question

A particle of mass \(m\) and charge \(q\) is placed at rest in a uniform electric tired \(E\) and then released. The kinetic energy attained by the particle after moving a distance \(\mathrm{y}\), is
(a) qEy
(b) \(\mathrm{qE}^{2} \mathrm{y}\)
(c) \(q E y^{2}\)
(d) \(q^{2} E y\)

Answer 1

Correct option (a) qEy
Explanation:
$$
\begin{aligned}
&\text { As } v^{2}=0^{2}+2 a y=2(F / m) y=2\left(\frac{q E}{m}\right) y \\
&\text { K.E. }=\frac{1}{2} m v^{2} \\
&\therefore \text { K.E. }=\frac{1}{2} m\left[2 \frac{(q E)}{m} y\right] \Rightarrow \text { K.E. }=q E y
\end{aligned}
$$

Answer 2

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Answer 3

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