Correct option (d) \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\)
Explanation:
Empirical formula of compound is \(\mathrm{CH}_{2} \mathrm{O}\)
Empirical formula mass \(=12+2+16=30\)
Molecular weight of compound \(=180\)
As, \(n=\frac{\text { molecular mass }}{\text { empirical mass }}=\frac{180}{30}=6\)
Therefore, molecular formula of compound is \(\left(\mathrm{CH}_{2} \mathrm{O}\right)_{6}=\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\)
