The correct option is: (b) \(8.4\)
Explanation:
Normality \((\mathrm{N})=1.5\)
We know that equivalent weight of \(\mathrm{H}_{2} \mathrm{O}_{2}\) is 17 and strength of \(\mathrm{H}_{2} \mathrm{O}_{2}=\) Normality \(\mathrm{x}\) Equivalent weight
$$
\begin{aligned}
&=1.5 \times 17=25.5 \\
&2 \mathrm{H}_{2} \mathrm{O}_{2} \rightarrow 2 \mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2} \\
&(2 \times 34=68 \mathrm{~g}) \quad(22.4 \mathrm{~L})
\end{aligned}
$$
Since 68 grams of \(\mathrm{H}_{2} \mathrm{O}_{2}\) produces \(22.4\) litres oxygen at NTP, therefore \(25.5\) grams of \(\mathrm{H}_{2} \mathrm{O}_{2}\) will produce
\(=22.4 / 68 \times 25.5=8.4\) litre of oxygen
Thus, volume strength of given \(\mathrm{H}_{2} \mathrm{O}_{2}\) solution is \(8.4\).
