The correct answer is
$$
\begin{array}{ccc}
2 \mathrm{Al}_{(\mathrm{s})} & + & 3 \mathrm{H}_{2} \mathrm{SO}_{4(\mathrm{aq})} & \longrightarrow \\
\text { Aluminium } & \text { Sulphuric } & \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3(\mathrm{aq})} & +3 \mathrm{H}_{2(\mathrm{~g})} \\
& & \text { Aluminium } & \text { Hydrogen } \\
& \text { acid (dil.) } & \text { sulphate } &
\end{array}
$$
ii.
\(\begin{array}{cccc}\mathrm{Na}_{2} \mathrm{CO}_{3(\mathrm{~s})} & 2 \mathrm{HCl}_{(\mathrm{aq})} \longrightarrow & 2 \mathrm{NaCl}_{(\mathrm{aq})} & +\mathrm{H}_{2} \mathrm{O}_{(l)} & +\mathrm{CO}_{2(\mathrm{~g})} \\ \text { Sodium } & \text { Hydrochloric } & \text { Sodium } & \text { Water } & \text { Carbon } \\ \text { carbonate } & \text { acid (dil.) } & \text { chloride } & & \text { dioxide }\end{array}\)
iii.
\(\begin{array}{cccc}\mathrm{Ca}(\mathrm{OH})_{2(\text { aq })} & +\mathrm{CO}_{2(\mathrm{~g})} & \longrightarrow & \mathrm{CaCO}_{3(\mathrm{~s})} \\ \text { Calcium } & \begin{array}{c}\text { Carbon } \\ \text { hydroxide } \\ \text { dioxide }\end{array} & \begin{array}{c}\text { Calcium } \\ \text { carbonate }\end{array} & \text { Water } \\ \text { (Lime water) } & & & \end{array}\)
