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Let \(f(x)=1-\sqrt{\left(x^{2}\right)}\) where the square root is to be taken positive, then
(A) f has no extrema at \(x=0\)
(B) \(f\) has minima at \(x=0\)
(C) f has maxima at \(x=0\)
(D) f' exists at 0

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Ans: (C)
Hint : \(f(x)=1-|x|, f\) has maxima at \(x=0\)
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