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Let $f(x)=1-\sqrt{\left(x^{2}\right)}$ where the square root is to be taken positive, then

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asked Dec 10, 2021 in Sets, relations and functions by kritika (90.1k points)
edited Dec 26, 2021 by kritika

Let

$f(x)=1-\sqrt{\left(x^{2}\right)}$ where the square root is to be taken positive, then
(A) f has no extrema at

$x=0$
(B)

$f$ has minima at

$x=0$
(C) f has maxima at

$x=0$
(D) f' exists at 0

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3 Answers

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answered Dec 26, 2021 by kritika (90.1k points)

Ans: (C)
Hint :

$f(x)=1-|x|, f$ has maxima at

$x=0$

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